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Alfred Melch 2 years ago
parent 4534eccffd
commit 4e8c71543c

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# This file is automatically @generated by Cargo.
# It is not intended for manual editing.
version = 3
[[package]]
name = "day14"
version = "0.1.0"
dependencies = [
"itertools",
]
[[package]]
name = "either"
version = "1.6.1"
source = "registry+https://github.com/rust-lang/crates.io-index"
checksum = "e78d4f1cc4ae33bbfc157ed5d5a5ef3bc29227303d595861deb238fcec4e9457"
[[package]]
name = "itertools"
version = "0.10.3"
source = "registry+https://github.com/rust-lang/crates.io-index"
checksum = "a9a9d19fa1e79b6215ff29b9d6880b706147f16e9b1dbb1e4e5947b5b02bc5e3"
dependencies = [
"either",
]

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[package]
name = "day14"
version = "0.1.0"
edition = "2021"
# See more keys and their definitions at https://doc.rust-lang.org/cargo/reference/manifest.html
[dependencies]
itertools = "0.10.0"

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https://adventofcode.com/2021/day/14
## \--- Day 14: Extended Polymerization ---
The incredible pressures at this depth are starting to put a strain on your
submarine. The submarine has
[polymerization](https://en.wikipedia.org/wiki/Polymerization) equipment that
would produce suitable materials to reinforce the submarine, and the nearby
volcanically-active caves should even have the necessary input elements in
sufficient quantities.
The submarine manual contains instructions for finding the optimal polymer
formula; specifically, it offers a _polymer template_ and a list of _pair
insertion_ rules (your puzzle input). You just need to work out what polymer
would result after repeating the pair insertion process a few times.
For example:
[code]
NNCB
CH -> B
HH -> N
CB -> H
NH -> C
HB -> C
HC -> B
HN -> C
NN -> C
BH -> H
NC -> B
NB -> B
BN -> B
BB -> N
BC -> B
CC -> N
CN -> C
[/code]
The first line is the _polymer template_ \- this is the starting point of the
process.
The following section defines the _pair insertion_ rules. A rule like `AB ->
C` means that when elements `A` and `B` are immediately adjacent, element `C`
should be inserted between them. These insertions all happen simultaneously.
So, starting with the polymer template `NNCB`, the first step simultaneously
considers all three pairs:
* The first pair (`NN`) matches the rule `NN -> C`, so element `_C_` is inserted between the first `N` and the second `N`.
* The second pair (`NC`) matches the rule `NC -> B`, so element `_B_` is inserted between the `N` and the `C`.
* The third pair (`CB`) matches the rule `CB -> H`, so element `_H_` is inserted between the `C` and the `B`.
Note that these pairs overlap: the second element of one pair is the first
element of the next pair. Also, because all pairs are considered
simultaneously, inserted elements are not considered to be part of a pair
until the next step.
After the first step of this process, the polymer becomes `N _C_ N _B_ C _H_
B`.
Here are the results of a few steps using the above rules:
[code]
Template: NNCB
After step 1: NCNBCHB
After step 2: NBCCNBBBCBHCB
After step 3: NBBBCNCCNBBNBNBBCHBHHBCHB
After step 4: NBBNBNBBCCNBCNCCNBBNBBNBBBNBBNBBCBHCBHHNHCBBCBHCB
[/code]
This polymer grows quickly. After step 5, it has length 97; After step 10, it
has length 3073. After step 10, `B` occurs 1749 times, `C` occurs 298 times,
`H` occurs 161 times, and `N` occurs 865 times; taking the quantity of the
most common element (`B`, 1749) and subtracting the quantity of the least
common element (`H`, 161) produces `1749 - 161 = _1588_`.
Apply 10 steps of pair insertion to the polymer template and find the most and
least common elements in the result. _What do you get if you take the quantity
of the most common element and subtract the quantity of the least common
element?_

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NNCB
CH -> B
HH -> N
CB -> H
NH -> C
HB -> C
HC -> B
HN -> C
NN -> C
BH -> H
NC -> B
NB -> B
BN -> B
BB -> N
BC -> B
CC -> N
CN -> C

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Template: NNCB
After step 1: NCNBCHB
After step 2: NBCCNBBBCBHCB
After step 3: NBBBCNCCNBBNBNBBCHBHHBCHB
After step 4: NBBNBNBBCCNBCNCCNBBNBBNBBBNBBNBBCBHCBHHNHCBBCBHCB

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CKKOHNSBPCPCHVNKHFFK
KO -> C
SO -> S
BF -> V
VN -> B
OV -> K
VH -> O
KV -> N
KB -> F
NB -> C
HS -> K
PF -> B
HB -> N
OC -> H
FS -> F
VV -> S
KF -> C
FN -> F
KP -> S
HO -> N
NH -> K
OO -> S
FB -> C
BP -> F
CH -> N
SN -> O
KN -> B
CV -> O
CC -> B
VB -> C
PH -> V
CO -> K
KS -> K
BK -> N
FH -> S
PV -> H
CB -> P
FO -> F
BB -> K
OB -> C
HH -> F
ON -> O
FK -> B
NF -> F
SV -> F
CP -> H
SS -> B
OP -> H
NS -> O
HK -> N
BC -> P
NV -> V
VS -> F
PC -> V
CS -> F
NP -> V
PS -> F
VC -> F
KK -> S
PO -> P
HF -> H
KC -> P
SF -> N
BV -> N
FF -> V
FV -> V
BO -> N
OS -> C
OF -> H
CN -> S
NO -> O
NC -> B
VK -> C
HN -> B
PK -> N
SK -> S
HV -> F
BH -> B
OK -> S
VO -> B
BS -> H
PP -> N
SC -> K
BN -> P
FC -> S
SB -> B
SH -> H
NN -> V
NK -> N
VF -> H
CF -> F
PB -> C
SP -> P
KH -> C
VP -> N
CK -> H
HP -> P
FP -> B
HC -> O
PN -> F
OH -> H

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use itertools::Itertools;
use std::collections::HashMap;
use std::io::stdin;
use std::io::BufRead;
fn main() {
let stdin = stdin();
let mut lines = stdin.lock().lines().map(|l| l.unwrap());
let polymer_template = lines.next().unwrap();
lines.next();
let mut insertion_rules = HashMap::new();
for line in lines {
let mut elements = line.chars().filter(|c| c.is_ascii_alphabetic());
let a = elements.next().unwrap();
let b = elements.next().unwrap();
let c = elements.next().unwrap();
let pair = (a, b);
insertion_rules.insert(pair, c);
}
dbg!(&polymer_template);
println!("Insertion rules: {:?}", insertion_rules);
let mut tuple_counter: HashMap<(char, char), i64> = HashMap::new();
for tuple in polymer_template.chars().tuple_windows() {
*tuple_counter.entry(tuple).or_insert(0) += 1;
}
let mut step = 0;
loop {
let mut next_counter = HashMap::new();
for ((a, b), amount) in tuple_counter {
if let Some(c) = insertion_rules.get(&(a, b)) {
let c = *c;
*next_counter.entry((a, c)).or_insert(0) += amount;
*next_counter.entry((c, b)).or_insert(0) += amount;
}
}
let length = next_counter.values().sum::<i64>() + 1;
tuple_counter = next_counter;
step += 1;
println!("After step {}: Length {}", step, length);
if step >= 40 {
break;
}
}
let mut element_counter = HashMap::new();
for ((a, b), amount) in tuple_counter {
*element_counter.entry(a).or_insert(0) += amount;
*element_counter.entry(b).or_insert(0) += amount;
}
let first_element = polymer_template.chars().next().unwrap();
let last_element = polymer_template.chars().last().unwrap();
*element_counter.entry(first_element).or_insert(0) += 1;
*element_counter.entry(last_element).or_insert(0) += 1;
for amount in element_counter.values_mut() {
*amount >>= 1;
}
println!("Element counter {:?}", element_counter);
let mut amounts: Vec<&i64> = element_counter.values().collect();
amounts.sort();
let least_common = amounts.get(0).unwrap();
let most_common = amounts.last().unwrap();
let answer = *most_common - *least_common;
println!("{:?}", amounts);
dbg!(answer);
}
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