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80 lines
1.9 KiB
Python
80 lines
1.9 KiB
Python
6 years ago
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from time import sleep
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m = []
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old_m = dict()
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with open('input.txt', 'r') as f:
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for line in f.readlines():
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row = []
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for sym in line.strip():
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row.append(sym)
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m.append(row)
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def print_map(m):
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for row in m:
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print(''.join(row))
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def get_adjacent(x, y):
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adj = []
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for i in [-1, 0, 1]:
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for j in [-1, 0, 1]:
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if not (i == 0 and j == 0):
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if x + i < 0 or y + j < 0:
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continue
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try:
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adj.append(m[x + i][y + j])
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except:
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pass
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return adj
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def get_res_val(m):
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num_trees = sum([row.count('|') for row in m])
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num_lumb = sum([row.count('#') for row in m])
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return num_lumb * num_trees
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for i in range(1000000000):
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i = i + 1
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new_m = []
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for x, row in enumerate(m):
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new_row = []
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for y, sym in enumerate(row):
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adj = get_adjacent(x, y)
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num_trees = adj.count('|')
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num_lumb = adj.count('#')
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if sym == '.':
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res = '|' if num_trees >= 3 else sym
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elif sym == '|':
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res = '#' if num_lumb >= 3 else sym
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elif sym == '#':
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res = sym if num_lumb >= 1 and num_trees >= 1 else '.'
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new_row.append(res)
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new_m.append(new_row)
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m = new_m
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if m in old_m.values():
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for j, tmp in old_m.items():
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if tmp == m:
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break
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print(f'Loop detected: {j} and {i} are the same')
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break
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old_m[i] = m
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if i % 100 == 0:
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print(i, get_res_val(m))
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loop_start = j
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first_iteration = i
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gap = first_iteration - loop_start
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tmp = (1000000000 - loop_start) % gap
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print('gap', gap)
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print('tmp', tmp)
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print(get_res_val(old_m[loop_start + tmp]))
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print(get_res_val(old_m[440]))
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# print_map(m)
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# print()
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# print_map(old_m[j])
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